x^2+16x+12=0

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Solution for x^2+16x+12=0 equation:


Simplifying
x2 + 16x + 12 = 0

Reorder the terms:
12 + 16x + x2 = 0

Solving
12 + 16x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-12' to each side of the equation.
12 + 16x + -12 + x2 = 0 + -12

Reorder the terms:
12 + -12 + 16x + x2 = 0 + -12

Combine like terms: 12 + -12 = 0
0 + 16x + x2 = 0 + -12
16x + x2 = 0 + -12

Combine like terms: 0 + -12 = -12
16x + x2 = -12

The x term is 16x.  Take half its coefficient (8).
Square it (64) and add it to both sides.

Add '64' to each side of the equation.
16x + 64 + x2 = -12 + 64

Reorder the terms:
64 + 16x + x2 = -12 + 64

Combine like terms: -12 + 64 = 52
64 + 16x + x2 = 52

Factor a perfect square on the left side:
(x + 8)(x + 8) = 52

Calculate the square root of the right side: 7.211102551

Break this problem into two subproblems by setting 
(x + 8) equal to 7.211102551 and -7.211102551.

Subproblem 1

x + 8 = 7.211102551 Simplifying x + 8 = 7.211102551 Reorder the terms: 8 + x = 7.211102551 Solving 8 + x = 7.211102551 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + x = 7.211102551 + -8 Combine like terms: 8 + -8 = 0 0 + x = 7.211102551 + -8 x = 7.211102551 + -8 Combine like terms: 7.211102551 + -8 = -0.788897449 x = -0.788897449 Simplifying x = -0.788897449

Subproblem 2

x + 8 = -7.211102551 Simplifying x + 8 = -7.211102551 Reorder the terms: 8 + x = -7.211102551 Solving 8 + x = -7.211102551 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + x = -7.211102551 + -8 Combine like terms: 8 + -8 = 0 0 + x = -7.211102551 + -8 x = -7.211102551 + -8 Combine like terms: -7.211102551 + -8 = -15.211102551 x = -15.211102551 Simplifying x = -15.211102551

Solution

The solution to the problem is based on the solutions from the subproblems. x = {-0.788897449, -15.211102551}

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